document.write( "Question 172704: I have a word problem that has been driving me crazy all night. I believe I have my setups, but I'm not sure. A number between 300 and 400 is forty times the sum of its digits. The tens digit is 6 more than the units digit. Find the number. Here is my setups: 300 + 10t + u = 40 (h + t + u), t = u + 6. Somewhere in figuring I get lost. Thanks for any help you can give. \n" ); document.write( "
Algebra.Com's Answer #127550 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A number between 300 and 400 is forty times the sum of its digits. The tens digit is 6 more than the units digit. Find the number.
\n" ); document.write( "----------------
\n" ); document.write( "The number must look like 3tu where t is the tensdigit and u is the units digit.
\n" ); document.write( "-------------------------------
\n" ); document.write( "Equations:
\n" ); document.write( "300 + 10t + u = 40(3+t+u)
\n" ); document.write( "t = u + 6
\n" ); document.write( "=====================
\n" ); document.write( "Simplify the first equation:
\n" ); document.write( "10t + u = -300 +120 + 40t + 40u
\n" ); document.write( "-30t -39u = -180
\n" ); document.write( "10t + 13u = 60
\n" ); document.write( "---------------------------
\n" ); document.write( "Substitute t = u+6 to solvefor \"u\":
\n" ); document.write( "10(u+6) +13u = 60
\n" ); document.write( "10u + 60 + 13u = 60
\n" ); document.write( "3u =0
\n" ); document.write( "u = 0
\n" ); document.write( "-----------------
\n" ); document.write( "Therefore t = 0+6 = 6
\n" ); document.write( "-----------------
\n" ); document.write( "Number: 360
\n" ); document.write( "================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );