document.write( "Question 172655: wORKLOAD =10000 APPRAISALS
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document.write( "7000 rESIDENTAIL
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document.write( "2500 cOMMERCIAL
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document.write( "500 iNDUDTRIAL\r
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document.write( "5 RESIDENTIAL OR COMMERCIAL PROPERTIES CAN BE DONE IN ONE DAY AND 2 INDUSTRIAL PROPERTIES CAN BE DONE IN ONE DAY. hOW MANY APPRAISERS ARE REQUIRED IF WE ASSUME A 240/DAY WORKYEAR? \n" );
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Algebra.Com's Answer #127513 by Mathtut(3670) ![]() You can put this solution on YOUR website! lets call residents,commercial and industrial r,c,and i \n" ); document.write( ": \n" ); document.write( "5r/day \n" ); document.write( "5c/day \n" ); document.write( "2i/day \n" ); document.write( ": \n" ); document.write( "7000/5=1400 work days \n" ); document.write( "2500/5=500 work days \n" ); document.write( "500/2=250 work days \n" ); document.write( ": \n" ); document.write( "total work days to appraise the 10000 appraisals is 2150 work days \n" ); document.write( "if each person works 240 days a year then the number needed would be \n" ); document.write( ": \n" ); document.write( "2150/240=8.95 rounding up \n" ); document.write( ": \n" ); document.write( "9 appraisers are needed assuming of course each appraiser can do any of the 3 types of appraisals.... \n" ); document.write( " |