document.write( "Question 172638This question is from textbook
\n" ); document.write( ": Ineed your help once again I try own my own and my answer are looking craazt help is needed. Thank you so much\r
\n" ); document.write( "\n" ); document.write( "Steve traveled 200 miles at a certain speed. Had he gone 10mph faster, the trip would have taken 1 hour less. Find the speed of his vehicle\r
\n" ); document.write( "\n" ); document.write( "can you show me this one too.\r
\n" ); document.write( "\n" ); document.write( "The Hudson River flows at a rate of 3 miles per hour. A patrol boat travels 60 miles upriver, and returns in a total time of 9 hours. What is the speed of the boat in still water?\r
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Algebra.Com's Answer #127498 by Mathtut(3670)\"\" \"About 
You can put this solution on YOUR website!
I set up the equations you solve
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\n" ); document.write( "d=rt........in both instances distance is equal
\n" ); document.write( "lets call the rate of the slow trip r and time t
\n" ); document.write( "lets call the rate of the fast trip r+10 and time(t-1)
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\n" ); document.write( "so 200=rt...eq 1
\n" ); document.write( "...200=(r+10)(t-1)..eq 2
\n" ); document.write( ":change eq 1 to t=200/r and substitute it into eq 2 and solve for r...this will involves a quadratic equation again
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\n" ); document.write( "\"200=%28r%2B10%29%28%28200%2Fr%29-1%29\"
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\n" ); document.write( "\"200=%28r%2B10%29%28%28200-r%29%2Fr%29\"
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\n" ); document.write( "\"200r=%28r%2B10%29%28200-r%29\"
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\n" ); document.write( "\"200r=200r-r%5E2%2B2000-10r\"
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\n" ); document.write( "\"r%5E2%2B10r-2000=0\"\r
\n" ); document.write( "\n" ); document.write( "throw out negative value\"system%28r=40%2Cr=-50%29\"
\n" ); document.write( "so \"highlight%28r=40%29\"mph and \"highlight%28r%2B10%29\"=50mph
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ar%5E2%2Bbr%2Bc=0\" (in our case \"1r%5E2%2B10r%2B-2000+=+0\") has the following solutons:
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\n" ); document.write( " \"r%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2810%29%5E2-4%2A1%2A-2000=8100\".
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\n" ); document.write( " Discriminant d=8100 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-10%2B-sqrt%28+8100+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"r%5B1%5D+=+%28-%2810%29%2Bsqrt%28+8100+%29%29%2F2%5C1+=+40\"
\n" ); document.write( " \"r%5B2%5D+=+%28-%2810%29-sqrt%28+8100+%29%29%2F2%5C1+=+-50\"
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\n" ); document.write( " Quadratic expression \"1r%5E2%2B10r%2B-2000\" can be factored:
\n" ); document.write( " \"1r%5E2%2B10r%2B-2000+=+1%28r-40%29%2A%28r--50%29\"
\n" ); document.write( " Again, the answer is: 40, -50.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B10%2Ax%2B-2000+%29\"

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\n" ); document.write( "Let s= speed of the boat in still water
\n" ); document.write( "The current =3 mi/hr
\n" ); document.write( "we know that d=rt or d/r=t for this problem we must break this up into 2 parts
\n" ); document.write( "(distance upriver)/(rate going upriver)
\n" ); document.write( "+ (distance downriver)/(rate going downriver) = 9 hrs
\n" ); document.write( ":the we know the distance is 60 each way
\n" ); document.write( "the rate going up stream is 60/s-3
\n" ); document.write( "the rate going down stream is 60/s+3
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\n" ); document.write( "so we have \"60%2F%28s-3%29%2B60%2F%28s%2B3%29=9\"again a quadratic equation
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\n" ); document.write( "multiply each term by (s+3)(s-3)
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\n" ); document.write( "\"60%28s%2B3%29%2B60%28s-3%29=9%28s%2B3%29%28s-3%29\"
\n" ); document.write( "\"60s%2B180%2B60s-180=9%28s%5E2-9%29\"
\n" ); document.write( "\"120s=9s%5E2-81\"
\n" ); document.write( "\"9s%5E2-120s-81=0\"
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\n" ); document.write( "drop the negative value\"system%28s=13.98%2Cs=-.64%29\"
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\n" ); document.write( "so \"highlight%28s=14%29\" mph\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"as%5E2%2Bbs%2Bc=0\" (in our case \"9s%5E2%2B-120s%2B-81+=+0\") has the following solutons:
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\n" ); document.write( " \"s%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-120%29%5E2-4%2A9%2A-81=17316\".
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\n" ); document.write( " Discriminant d=17316 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--120%2B-sqrt%28+17316+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"s%5B1%5D+=+%28-%28-120%29%2Bsqrt%28+17316+%29%29%2F2%5C9+=+13.9772373998204\"
\n" ); document.write( " \"s%5B2%5D+=+%28-%28-120%29-sqrt%28+17316+%29%29%2F2%5C9+=+-0.643904066487102\"
\n" ); document.write( "
\n" ); document.write( " Quadratic expression \"9s%5E2%2B-120s%2B-81\" can be factored:
\n" ); document.write( " \"9s%5E2%2B-120s%2B-81+=+9%28s-13.9772373998204%29%2A%28s--0.643904066487102%29\"
\n" ); document.write( " Again, the answer is: 13.9772373998204, -0.643904066487102.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+9%2Ax%5E2%2B-120%2Ax%2B-81+%29\"

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