document.write( "Question 172638This question is from textbook
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document.write( ": Ineed your help once again I try own my own and my answer are looking craazt help is needed. Thank you so much\r
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document.write( "Steve traveled 200 miles at a certain speed. Had he gone 10mph faster, the trip would have taken 1 hour less. Find the speed of his vehicle\r
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document.write( "can you show me this one too.\r
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document.write( "The Hudson River flows at a rate of 3 miles per hour. A patrol boat travels 60 miles upriver, and returns in a total time of 9 hours. What is the speed of the boat in still water?\r
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Algebra.Com's Answer #127498 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! I set up the equations you solve \n" ); document.write( ": \n" ); document.write( "d=rt........in both instances distance is equal \n" ); document.write( "lets call the rate of the slow trip r and time t \n" ); document.write( "lets call the rate of the fast trip r+10 and time(t-1) \n" ); document.write( ": \n" ); document.write( "so 200=rt...eq 1 \n" ); document.write( "...200=(r+10)(t-1)..eq 2 \n" ); document.write( ":change eq 1 to t=200/r and substitute it into eq 2 and solve for r...this will involves a quadratic equation again \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "throw out negative value \n" ); document.write( "so \n" ); document.write( ":\r \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Let s= speed of the boat in still water \n" ); document.write( "The current =3 mi/hr \n" ); document.write( "we know that d=rt or d/r=t for this problem we must break this up into 2 parts \n" ); document.write( "(distance upriver)/(rate going upriver) \n" ); document.write( "+ (distance downriver)/(rate going downriver) = 9 hrs \n" ); document.write( ":the we know the distance is 60 each way \n" ); document.write( "the rate going up stream is 60/s-3 \n" ); document.write( "the rate going down stream is 60/s+3 \n" ); document.write( ": \n" ); document.write( "so we have \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "multiply each term by (s+3)(s-3) \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "drop the negative value \n" ); document.write( ": \n" ); document.write( "so \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
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