document.write( "Question 172633This question is from textbook Algebra Structure and Method Book 1
\n" ); document.write( ": The numerator equals the sum of the two digits in the denominator. The value of the fraction is 1/4. When both numerator and demonimator are increased by 3, the resulting fraction as the value 1/3. Find the original fraction. \n" ); document.write( "

Algebra.Com's Answer #127497 by Mathtut(3670) $\"\"$ $\"About$

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lets call the numerator a and the denominator b
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\n" ); document.write( "a/b=1/4--->4a=b....eq 1
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\n" ); document.write( "(a+3)/(b+3)=1/3--->3a+9=b+3--->3a=b-6...eq 2
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\n" ); document.write( "take b's value from eq 1 and plug it into eq 2
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\n" ); document.write( "3a=4a-6
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\n" ); document.write( " $\"highlight%28a=6%29\"$
\n" ); document.write( " $\"highlight%28b=4%286%29=24%29\"$ \r
\n" ); document.write( "\n" ); document.write( "6/24=1/4\r
\n" ); document.write( "\n" ); document.write( "(6+3)/(24+3)=9/27=1/3
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