document.write( "Question 172476This question is from textbook Introductory Algebra
\n" );
document.write( ": Solve the equation\r
\n" );
document.write( "\n" );
document.write( "y = sqrt (3y + 10) \n" );
document.write( "
Algebra.Com's Answer #127458 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! y = sqrt (3y + 10) \n" ); document.write( "Y^2=3Y+10 \n" ); document.write( "Y^2-3Y-10=0 \n" ); document.write( "(Y-5)(Y+2)=0 \n" ); document.write( "Y-5=0 \n" ); document.write( "Y=5 ANS. \n" ); document.write( "Y+2=0 \n" ); document.write( "Y=-2 ANS. \n" ); document.write( "PROOFS: \n" ); document.write( "5=SQRT(3*5+10) \n" ); document.write( "5=SQRT(15+10) \n" ); document.write( "5=SQRT25 \n" ); document.write( "5=5 \n" ); document.write( "-2=SQRT(3*-2+10) \n" ); document.write( "-2=SQRT(-6+10) \n" ); document.write( "-2=SQRT4 \n" ); document.write( "-2=-2 \n" ); document.write( " |