document.write( "Question 172476This question is from textbook Introductory Algebra
\n" ); document.write( ": Solve the equation\r
\n" ); document.write( "\n" ); document.write( "y = sqrt (3y + 10)
\n" ); document.write( "

Algebra.Com's Answer #127458 by checkley77(12844)\"\" \"About 
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y = sqrt (3y + 10)
\n" ); document.write( "Y^2=3Y+10
\n" ); document.write( "Y^2-3Y-10=0
\n" ); document.write( "(Y-5)(Y+2)=0
\n" ); document.write( "Y-5=0
\n" ); document.write( "Y=5 ANS.
\n" ); document.write( "Y+2=0
\n" ); document.write( "Y=-2 ANS.
\n" ); document.write( "PROOFS:
\n" ); document.write( "5=SQRT(3*5+10)
\n" ); document.write( "5=SQRT(15+10)
\n" ); document.write( "5=SQRT25
\n" ); document.write( "5=5
\n" ); document.write( "-2=SQRT(3*-2+10)
\n" ); document.write( "-2=SQRT(-6+10)
\n" ); document.write( "-2=SQRT4
\n" ); document.write( "-2=-2
\n" ); document.write( "
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