document.write( "Question 172588: 1/3logbX + 3logbY - 4logbX = \n" ); document.write( "
Algebra.Com's Answer #127450 by Alan3354(69443) You can put this solution on YOUR website! 1/3logbX + 3logbY - 4logbX = \n" ); document.write( "= log(x^(1/3)) + log(y^3) - log(x^4) (all the same base) \n" ); document.write( "= log(y^3*x^(1/3)/x^4) \n" ); document.write( "= \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |