document.write( "Question 172588: 1/3logbX + 3logbY - 4logbX = \n" ); document.write( "
Algebra.Com's Answer #127450 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
1/3logbX + 3logbY - 4logbX =
\n" ); document.write( "= log(x^(1/3)) + log(y^3) - log(x^4) (all the same base)
\n" ); document.write( "= log(y^3*x^(1/3)/x^4)
\n" ); document.write( "= \"log%28b%2C%28y%5E3%2Fx%5E%2811%2F3%29%29%29\"\r
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