document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=172530>Question 172530</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a triangle is 38 feet.  the length is 17 feet less than five times the width.  What are the dimensions of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #127397 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=127397\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a triangle is 38 feet. the length is 17 feet less than five times the width. What are the dimensions of the rectangle?<BR>\n" );
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document.write( "I went past this one a few times because it says \"triangle\", then it says \"rectangle.\"  I think it's a rectangle.<BR>\n" );
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document.write( "P = 2L + 2W = 38 (perimeter = 2*width + 2*length)<BR>\n" );
document.write( "L + W = 19<BR>\n" );
document.write( "L = 5W - 17<BR>\n" );
document.write( "Sub for L<BR>\n" );
document.write( "5W-17 + W = 19<BR>\n" );
document.write( "6W = 36<BR>\n" );
document.write( "W = 6 feet<BR>\n" );
document.write( "L = 13 feet\r<BR>\n" );
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