document.write( "Question 172465: Steve traveled 200 miles at a certain speed. Had he gone 10mph faster, the trip would have taken 1 hour less. Find the speed of his vehicle. \n" ); document.write( "
Algebra.Com's Answer #127381 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Steve traveled 200 miles at a certain speed. Had he gone 10mph faster, the trip \n" ); document.write( " would have taken 1 hour less. Find the speed of his vehicle. \n" ); document.write( ": \n" ); document.write( "Let s = original speed of the vehicle \n" ); document.write( "then \n" ); document.write( "(s+10) = the faster speed \n" ); document.write( ": \n" ); document.write( "Write a time equation, time = \n" ); document.write( ": \n" ); document.write( "original time = faster time + 1 hour \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply equation by s(s+10) \n" ); document.write( "s(s+10)* \n" ); document.write( "Results: \n" ); document.write( "200(s+10) = 200s + s^2 + 10s \n" ); document.write( ": \n" ); document.write( "200s + 2000 = 200s + s^2 + 10s \n" ); document.write( ": \n" ); document.write( "Arrange as quadratic equation: \n" ); document.write( "s^2 + 10s + 200s - 200s - 2000 = 0 \n" ); document.write( ": \n" ); document.write( "s^2 + 10s - 2000 = 0 \n" ); document.write( "Factors to: \n" ); document.write( "(s + 50)(x - 40) = 0 \n" ); document.write( ": \n" ); document.write( "s = + 40 mph is the original speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the times \n" ); document.write( "200/40 = 5 hrs \n" ); document.write( "200/50 = 4 hrs \n" ); document.write( " |