document.write( "Question 24045: It has been 7 years since my last algebra class. The answer is 8 but I am not sure how to solve this problem can you please help me :
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document.write( " 2/3(x+6)=1+ (4x-7)/3
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document.write( "I have tried common denominator of 6
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document.write( "4(x+6)= 1+2(4x-7)
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document.write( "4x+24=1+8x-14
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document.write( "4x+24=8x-13
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document.write( "stuck here\r
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document.write( "I tried 3 as common denominator also
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document.write( "3(x+6)= 1+3(4x-7)
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document.write( "3x+18 = 16x-28
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document.write( "-13x=-46
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document.write( "stuck here \n" );
document.write( "
Algebra.Com's Answer #12737 by PeterC(8)![]() ![]() ![]() You can put this solution on YOUR website! I am glad to see that you have tried to solve the problem yourself before asking for help. The problem with your solution is that you need to multiply both terms in the right-hand part by the common factor. That is, after multiplying by 6, you should have:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Actually, I would have multiplied by 3, the common factor in all of the denominators:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |