document.write( "Question 172483This question is from textbook Introductory Algebra
\n" ); document.write( ": Graph the quadratic equation and label the ordered pairs for the vertex and the y-intercept.\r
\n" ); document.write( "\n" ); document.write( "y = x^2 + x - 2 \n" ); document.write( "

Algebra.Com's Answer #127367 by jojo14344(1513) $\"\"$ $\"About$

You can put this solution on YOUR website!
A function written in the form ---> $\"f%28x%29=a%28x-h%29%5E2%2Bk\"$ , where (h,k) the vertex.
\n" ); document.write( "Given: $\"f%28x%29=x%5E2%2Bx-2\"$ , we complete the square:
\n" ); document.write( " $\"f%28x%29=%28x%5E2%2Bx%2B1%2F4%29highlight%28-1%2F4%29-2\"$ , Add $\"1%2F4\"$ , and also subtract $\"1%2F4\"$ so the expression won't change.
\n" ); document.write( "*Note: How we get $\"1%2F4\"$ ? Take half of the middle term constant (which in this case is \"1\") then squared it. ---> $\"%281%2F2%29%5E2=1%2F4\"$
\n" ); document.write( "Continuing;
\n" ); document.write( " $\"f%28x%29=%28x%2B1%2F2%29%5E2-2.25\"$ ----> $\"highlight%28h=-1%2F2%29\"$ , $\"highlight%28k=-2.25%29\"$
\n" ); document.write( "For the Y-Intercept:
\n" ); document.write( " $\"f%28x%29=0\"$
\n" ); document.write( " $\"f%280%29=0%5E2%2B0-2\"$
\n" ); document.write( "Therefore: Y-Intercept is $\"highlight%28-2%29\"$ \r
\n" ); document.write( "\n" ); document.write( "let's see the graph:
\n" ); document.write( "

\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo \n" ); document.write( "

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