document.write( "Question 172485This question is from textbook Prentice Hall Mathematics ALGEBRA 1
\n" ); document.write( ": How do you write an equation in slope-intercept form for a line that passes through (0,2) and is perpendicular to x= -7? \n" ); document.write( "
Algebra.Com's Answer #127361 by vleith(2983)\"\" \"About 
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perpendicular lines have slopes that are negative reciprocals of each other. So what is the slope of the line \"x+=+-7\"? That line is a vertical line. It's slope is undefined. However, you know that a horizontal line is perpendicular to a vertical one.\r
\n" ); document.write( "\n" ); document.write( "What is the slope of a horizontal line? 0\r
\n" ); document.write( "\n" ); document.write( "So you have a point (0,2) and a slope of 0
\n" ); document.write( "That means we are looking for a horizontal line that runs thru the point (0,2).
\n" ); document.write( "We already know that m = 0
\n" ); document.write( "\"y+=+mx+%2B++b\"
\n" ); document.write( "\"y+=+0%2Ax+%2B+b\"
\n" ); document.write( "\"2+=+0%2A0+%2B+b\"
\n" ); document.write( "\"2+=+b\"
\n" ); document.write( "The general formula for that line is
\n" ); document.write( "\"y+=+0%2Ax+%2B+2\"
\n" ); document.write( "\"y+=+2\"\r
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\n" ); document.write( "\n" ); document.write( "You can do a more general look this way:
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Solved by pluggable solver: FIND a line by slope and one point

\n" ); document.write( " What we know about the line whose equation we are trying to find out:
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  • it goes through point (0, 2)

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  • it has a slope of 0

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\n" ); document.write( " First, let's draw a diagram of the coordinate system with point (0, 2) plotted with a little blue dot:
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\n" ); document.write( " Write this down: the formula for the equation, given point \"x%5B1%5D%2C+y%5B1%5D\" and intercept a, is
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\n" ); document.write( " \"y=ax+%2B+%28y%5B1%5D-a%2Ax%5B1%5D%29\" (see a paragraph below explaining why this formula is correct)
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\n" ); document.write( " Given that a=0, and \"system%28+x%5B1%5D+=+0%2C+y%5B1%5D+=+2+%29+\", we have the equation of the line:
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\n" ); document.write( " \"y=0%2Ax+%2B+2\"
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\n" ); document.write( " Explanation: Why did we use formula \"y=ax+%2B+%28y%5B1%5D+-+a%2Ax%5B1%5D%29\" ? Explanation goes here. We are trying to find equation y=ax+b. The value of slope (a) is already given to us. We need to find b. If a point (\"x%5B1%5D\", \"y%5B1%5D\") lies on the line, it means that it satisfies the equation of the line. So, our equation holds for (\"x%5B1%5D\", \"y%5B1%5D\"): \"y%5B1%5D+=+a%2Ax%5B1%5D%2Bb\" Here, we know a, \"x%5B1%5D\", and \"y%5B1%5D\", and do not know b. It is easy to find out: \"b=y%5B1%5D-a%2Ax%5B1%5D\". So, then, the equation of the line is: \"+y=ax%2B%28y%5B1%5D-a%2Ax%5B1%5D%29+\".
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\n" ); document.write( " Here's the graph:
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