document.write( "Question 24045: It has been 7 years since my last algebra class. The answer is 8 but I am not sure how to solve this problem can you please help me :
\n" ); document.write( " 2/3(x+6)=1+ (4x-7)/3
\n" ); document.write( "I have tried common denominator of 6
\n" ); document.write( "4(x+6)= 1+2(4x-7)
\n" ); document.write( "4x+24=1+8x-14
\n" ); document.write( "4x+24=8x-13
\n" ); document.write( "stuck here\r
\n" ); document.write( "\n" ); document.write( "I tried 3 as common denominator also
\n" ); document.write( "3(x+6)= 1+3(4x-7)
\n" ); document.write( "3x+18 = 16x-28
\n" ); document.write( "-13x=-46
\n" ); document.write( "stuck here \n" ); document.write( "
Algebra.Com's Answer #12736 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Your mistake is that in both of your solutions, you forgot to multiply the 1 on the right side of the equation by the common denominator. This is what it should have been:\r
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\n" ); document.write( "\n" ); document.write( "2/3(x+6)=1+ (4x-7)/3
\n" ); document.write( "I have tried common denominator of 6
\n" ); document.write( "4(x+6)= 6+2(4x-7)
\n" ); document.write( "4x+24=6+8x-14
\n" ); document.write( "4x+24=8x-8
\n" ); document.write( "32 = 4x
\n" ); document.write( "x=8\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "In your second solution, there were a couple of other errors to clean up. See if this looks better?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I tried 3 as common denominator also
\n" ); document.write( "2(x+6)= 3+(4x-7)
\n" ); document.write( "2x+12 = 4x -4
\n" ); document.write( "16 = 2x
\n" ); document.write( "x=8\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( "
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