document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=172452>Question 172452</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i need help soving a substitution problom\r<BR>\n" );
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document.write( "2x-3y=-14<BR>\n" );
document.write( "3x-y=-7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #127350 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=127350\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x-3y=-14<BR>\n" );
document.write( "3x-y=-7<BR>\n" );
document.write( "y = 3x+7 (from the 2nd eqn)<BR>\n" );
document.write( "Sub into the 1st eqn<BR>\n" );
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document.write( "2x-3y=-14<BR>\n" );
document.write( "2x - 3(3x+7) = -14<BR>\n" );
document.write( "2x - 9x - 21 = -14<BR>\n" );
document.write( "-7x = 7<BR>\n" );
document.write( "x = -1<BR>\n" );
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document.write( "3x-y=-7<BR>\n" );
document.write( "3*(-1) - y = -7<BR>\n" );
document.write( "-3 - y = -7<BR>\n" );
document.write( "y = 4<BR>\n" );
document.write( " </SPAN>\n" );
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