document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=172451>Question 172451</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help solving a substitution problom\r<BR>\n" );
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document.write( "1/2x+y=2<BR>\n" );
document.write( "2x+3y=9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #127347 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=127347\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solving a substitution problom <BR>\n" );
document.write( "(1/2)x+y=2<BR>\n" );
document.write( "2x+3y=9<BR>\n" );
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document.write( "y = 2-(1/2)x<BR>\n" );
document.write( "Substitute for \"y\" in the 2nd foundation:<BR>\n" );
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document.write( "2x + 3(2-(1/2) = 9\r<BR>\n" );
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document.write( "2x + 6 - (3/2)x = 9<BR>\n" );
document.write( "(1/2)x = 3<BR>\n" );
document.write( "x = 6<BR>\n" );
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document.write( "Since y = 2-(1/2)x, y = 2-(1/2)6 = -1<BR>\n" );
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document.write( "Ans: x=6, y= -1<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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