document.write( "Question 172425: HELP!!\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 4 cm more than 3 times its width. If the area of the rectangle is 95 cm2, find the dimensions of the rectangle to the nearest thousandth.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #127333 by praseenakos@yahoo.com(507)\"\" \"About 
You can put this solution on YOUR website!
Question:\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 4 cm more than 3 times its width. If the area of the rectangle is 95 cm2, find the dimensions of the rectangle to the nearest thousandth.\r
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "Area of a rectangle is given by the formula,\r
\n" ); document.write( "\n" ); document.write( "A = length * width\r
\n" ); document.write( "\n" ); document.write( "Given, A = \"+95+cm%5E2\"\r
\n" ); document.write( "\n" ); document.write( "length = 4 cm more than 3 times its width\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let us assume that width = x cm\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "==> length = 3x + 4 (because, length = 4 cm more than 3 times its width)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "so... area = length * width = (3x + 4) * x\r
\n" ); document.write( "\n" ); document.write( " 95 = (3x + 4) * x\r
\n" ); document.write( "\n" ); document.write( "==> 95 = 3x*x + 4* x\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "==> \"+95+=+3x%5E2+%2B+4x+\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "==> \"+3x%5E2+%2B+4x+-+95+=+0\"
\n" ); document.write( "this is a quadratic equation, you can solve it using quadratic formula\r
\n" ); document.write( "\n" ); document.write( "==> \"x+=+%28-4+%2B-+sqrt%28+%28-4%29%5E2-4%2A3%2A%28-95%29+%29%29%2F%282%2A3%29+\"
\n" ); document.write( "==> \"x+=+%28-4+%2B-+sqrt%28+16+%2B+1140+%29%29%2F%286%29+\" \r
\n" ); document.write( "\n" ); document.write( "==> \"x+=+%28-4+%2B-+sqrt%28+1156+%29%29%2F%286%29+\" \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "==> \"x+=+%28-4+%2B-+34%29%2F%286%29+\" \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "==> \"x+=+%28-4+%2B+34%29%2F%286%29+\" or \"x+=+%28-4+-+34%29%2F%286%29+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " ==> \"x+=+%2830%29%2F%286%29+\" or \"x+=+%28-38%29%2F%286%29+\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " ==> \"x+=+5+\" or \"x+=+-6.333+\"\r
\n" ); document.write( "\n" ); document.write( "here u can take the value x= 5 since negative value cant be a length measure\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "so width = 5 cm\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "and length = 3*5 + 4 = 15 + 4 = 19\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "so the dimensions are 19 cm and 5cm\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "hence the answer.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "hope u found it useful.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Regards.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Praseena\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );