document.write( "Question 24007: 5x+6y=12 How do I solve this system of linear equation?
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document.write( "3x-2y=-4 \n" );
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Algebra.Com's Answer #12728 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! SEE THE FOLLOWING AND COME BACK IF YOU HAVE DIFFICULTY.HERE C,CX,CY,CZ REFER TO YOUR D,DX,DY,DZ...JUST A DIFFERENCE IN NOMENCLATURE.I SHOWED IN DETAIL A 2X2 DETERMINANT AND THEN IN BRIEF A 3X3 DETERMINANT \n" ); document.write( "2x+y=4 \n" ); document.write( "3x-y=6 \n" ); document.write( "make a deteminant with coefficients of x (2,3)and y(1,-1) in the 2 eqns.call it C.(Actually for a determinant as you know ,the numbers are contained in vertical bars at either end like |xx|,but in the following the bars are omitted due to difficulty in depiction.you may assume the bars are present) \n" ); document.write( "C= \n" ); document.write( "..now use the constants (4,6)to replace coefficients of x(2,3) in the above determinant C...call it CX.. \n" ); document.write( "CX= \n" ); document.write( "..now use the constants (4,6)to replace coefficients of y(1,-1) in the above determinant C...call it CY.. \n" ); document.write( "CY= \n" ); document.write( "..now cramers rule says that \n" ); document.write( "(x/CX)=(y/CY)=(1/C)..so we get \n" ); document.write( "x/(-10)=y/0=1/-5 \n" ); document.write( "x=-10/-5=10/5=2 \n" ); document.write( "y=0/-5=0 \n" ); document.write( " \n" ); document.write( " |