document.write( "Question 24007: 5x+6y=12 How do I solve this system of linear equation?
\n" ); document.write( "3x-2y=-4
\n" ); document.write( "

Algebra.Com's Answer #12728 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
SEE THE FOLLOWING AND COME BACK IF YOU HAVE DIFFICULTY.HERE C,CX,CY,CZ REFER TO YOUR D,DX,DY,DZ...JUST A DIFFERENCE IN NOMENCLATURE.I SHOWED IN DETAIL A 2X2 DETERMINANT AND THEN IN BRIEF A 3X3 DETERMINANT
\n" ); document.write( "2x+y=4
\n" ); document.write( "3x-y=6
\n" ); document.write( "make a deteminant with coefficients of x (2,3)and y(1,-1) in the 2 eqns.call it C.(Actually for a determinant as you know ,the numbers are contained in vertical bars at either end like |xx|,but in the following the bars are omitted due to difficulty in depiction.you may assume the bars are present)
\n" ); document.write( "C=\"matrix%282%2C2%2C2%2C1%2C3%2C-1%29\"=2*(-1)-(1*3)=-5
\n" ); document.write( "..now use the constants (4,6)to replace coefficients of x(2,3) in the above determinant C...call it CX..
\n" ); document.write( "CX=\"matrix%282%2C2%2C4%2C1%2C6%2C-1%29\"=4*(-1)-1*6=-4-6=-10
\n" ); document.write( "..now use the constants (4,6)to replace coefficients of y(1,-1) in the above determinant C...call it CY..
\n" ); document.write( "CY=\"matrix%282%2C2%2C2%2C4%2C3%2C6%29\"=2*6-3*4=12=12=0
\n" ); document.write( "..now cramers rule says that
\n" ); document.write( "(x/CX)=(y/CY)=(1/C)..so we get
\n" ); document.write( "x/(-10)=y/0=1/-5
\n" ); document.write( "x=-10/-5=10/5=2
\n" ); document.write( "y=0/-5=0
\n" ); document.write( "
\n" ); document.write( "
\n" );