document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23986>Question 23986</A>: <I><SPAN STYLE=\"word-break: break-all;\"> determinants\r<BR>\n" );
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document.write( "2x+y=3<BR>\n" );
document.write( "5x+6y=4\r<BR>\n" );
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document.write( "[2 1]= 12-5=7<BR>\n" );
document.write( "[5 6]\r<BR>\n" );
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document.write( "x=[3 1]<BR>\n" );
document.write( "  [4 6]\r<BR>\n" );
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document.write( "then what??? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #12727 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=12727\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SEE THE FOLLOWING AND COME BACK IF YOU HAVE DIFFICULTY.HERE C,CX,CY,CZ REFER TO YOUR D,DX,DY,DZ...JUST A DIFFERENCE IN NOMENCLATURE.I SHOWED IN DETAIL A 2X2 DETERMINANT AND THEN IN BRIEF A 3X3 DETERMINANT<BR>\n" );
document.write( "2x+y=4<BR>\n" );
document.write( "3x-y=6<BR>\n" );
document.write( "make a deteminant with coefficients of x (2,3)and y(1,-1) in the 2 eqns.call it C.(Actually for a determinant as you know ,the numbers are contained in vertical bars at either end like |xx|,but in the following the bars are omitted due to difficulty in depiction.you may assume the bars are present)<BR>\n" );
document.write( "C=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=matrix%282%2C2%2C2%2C1%2C3%2C-1%29 ALIGN=MIDDLE  ALT=\"matrix%282%2C2%2C2%2C1%2C3%2C-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >=2*(-1)-(1*3)=-5<BR>\n" );
document.write( "..now use the constants (4,6)to replace coefficients of x(2,3) in the above determinant C...call it CX..<BR>\n" );
document.write( "CX=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=matrix%282%2C2%2C4%2C1%2C6%2C-1%29 ALIGN=MIDDLE  ALT=\"matrix%282%2C2%2C4%2C1%2C6%2C-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >=4*(-1)-1*6=-4-6=-10<BR>\n" );
document.write( "..now use the constants (4,6)to replace coefficients of y(1,-1) in the above determinant C...call it CY..<BR>\n" );
document.write( "CY=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=matrix%282%2C2%2C2%2C4%2C3%2C6%29 ALIGN=MIDDLE  ALT=\"matrix%282%2C2%2C2%2C4%2C3%2C6%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >=2*6-3*4=12=12=0<BR>\n" );
document.write( "..now cramers rule says that<BR>\n" );
document.write( "(x/CX)=(y/CY)=(1/C)..so we get<BR>\n" );
document.write( "x/(-10)=y/0=1/-5<BR>\n" );
document.write( "x=-10/-5=10/5=2<BR>\n" );
document.write( "y=0/-5=0<BR>\n" );
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