document.write( "Question 23995: can u help me with this equation: -3(h-6)=5(2h+3) \n" ); document.write( "
Algebra.Com's Answer #12723 by yhtong(11)\"\" \"About 
You can put this solution on YOUR website!
ok, heres what you do,
\n" ); document.write( "first solve all that you can solve. in this case its:\r
\n" ); document.write( "\n" ); document.write( "-3(h-6)=5(2h+3)
\n" ); document.write( "-3h+18=10h+15\r
\n" ); document.write( "\n" ); document.write( "then, bring all values that has the unknown for instance, -3h and 10h to the left hand side (LHS) and bring all the values without unknown to the right hand side (RHS) . Since -3h is already in the LHS, therefore you dont need to do anything to it. Its the same for 15 that is already in the RHS. That makes,\r
\n" ); document.write( "\n" ); document.write( "-3h-10h=15-18 (remember to change their sign from + to - or vice versa when
\n" ); document.write( " bringing them to the opposite side)\r
\n" ); document.write( "\n" ); document.write( "then, you factor the ones in the LHS\r
\n" ); document.write( "\n" ); document.write( "h(-3-10)=15-18\r
\n" ); document.write( "\n" ); document.write( "Since the unknown can be seperated with the coeficient, bring the coeficient, (-3-10) to the RHS but before that solve it first, solve the equation in the RHS as well\r
\n" ); document.write( "\n" ); document.write( "h(-13)=-3
\n" ); document.write( "h =-3/-13
\n" ); document.write( "h =3/13\r
\n" ); document.write( "\n" ); document.write( "therefore your answer is 3/13\r
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