document.write( "Question 24015: Solve the equation using the substitution method
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document.write( "6x+2y=16
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document.write( "-2x+y=-2 \n" );
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Algebra.Com's Answer #12722 by yhtong(11)![]() ![]() ![]() You can put this solution on YOUR website! your questions are:\r \n" ); document.write( "\n" ); document.write( "6x+2y=16 ------- 1 \n" ); document.write( "-2x+y=-2 ------- 2\r \n" ); document.write( "\n" ); document.write( "pick either equation 1 or 2, i would choose equation 2 because its easier. \n" ); document.write( "in equation 2 i would like to solve y. In this case, bring all numbers and unknown except y to the right hand side (RHS)\r \n" ); document.write( "\n" ); document.write( "y=-2+2x ------ 3(i will name this equation 3)\r \n" ); document.write( "\n" ); document.write( "next, substitute y in equation 3 to equation 1. That makes\r \n" ); document.write( "\n" ); document.write( "6x+2(-2+2x)=16. The equation in the brackets is the value of y in equation 3 that i chose earlier\r \n" ); document.write( "\n" ); document.write( "That makes\r \n" ); document.write( "\n" ); document.write( "6x-4+4x=16, solve this by using linear equation \n" ); document.write( "=6x+4x-4=16 \n" ); document.write( "=10x-4=16 \n" ); document.write( "=10x =16+4 \n" ); document.write( "=10x =20 \n" ); document.write( "=x =20/10 \n" ); document.write( "=x =2\r \n" ); document.write( "\n" ); document.write( "now that you know the value of x is 2, substitute the x into equation 3 to know what value is y\r \n" ); document.write( "\n" ); document.write( "y=-2+2x \n" ); document.write( "y=-2+2(2) \n" ); document.write( "y=-2+4 \n" ); document.write( "y=2\r \n" ); document.write( "\n" ); document.write( "now we have both x and y values and the values are \n" ); document.write( "x=2,y=2 \n" ); document.write( " \n" ); document.write( " |