document.write( "Question 24022: Please help me solve this question!!\r
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document.write( "The width of a rectangle measures W. The lenght of the rectangle measures 12 units more than the width. The area of the rectangle is W(W + 12). What is a reasonable domain for the lenght of this rectangle.\r
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document.write( "A. W > 0\r
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document.write( "B. W < 12\r
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document.write( "C. W > 12\r
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document.write( "D. W = 12\r
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document.write( "if you could help me with this it would mean a lot to me!! thanks!!! \n" );
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Algebra.Com's Answer #12721 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! The width of a rectangle measures W. The lenght of the rectangle measures 12 units more than the width. The area of the rectangle is W(W + 12). What is a reasonable domain for the lenght of this rectangle.\r \n" ); document.write( "\n" ); document.write( "A. W > 0\r \n" ); document.write( "\n" ); document.write( "B. W < 12\r \n" ); document.write( "\n" ); document.write( "C. W > 12\r \n" ); document.write( "\n" ); document.write( "D. W = 12\r \n" ); document.write( "\n" ); document.write( "if you could help me with this it would mean a lot to me!! thanks!!! \n" ); document.write( "you know width cannot be zero .it should some thing more than zero so w>0... \n" ); document.write( "now length is w+12..so length shoul be more than 0+12 or that is more than 12...so length >12 and width >0..now to your 4 choices ..they are not compatible with question.which mentions domain of length it is >12 as we saw but the symbol shown in answers is w always which stands for width as per our problem and whi=ch needs to be >0 ..so symbol wise A...W>0 is correct ,but problem write up wise length >12 is correct...which is not there in the choices..so you check with your book or teacher for misprint... \n" ); document.write( " |