document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=172153>Question 172153</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the number such that when 14 is added to two thirds of it, the result is one and a quater times the original number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #127181 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=127181\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the number such that when 14 is added to two thirds of it, the result is one and a quater times the original number.<BR>\n" );
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document.write( "EQUATION:\r<BR>\n" );
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document.write( "(2/3)x + 14 = (5/4)x\r<BR>\n" );
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document.write( "Multiply thru by 12 to get:<BR>\n" );
document.write( "8x + 12*14 = 15x<BR>\n" );
document.write( "7x = 12*14<BR>\n" );
document.write( "x = 12*2<BR>\n" );
document.write( "x = 24<BR>\n" );
document.write( "======================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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