document.write( "Question 172100: 1. Determine whether the following equations have a solution or not? Justify your answer.
\n" ); document.write( "a) x2 + 6x - 7 = 0
\n" ); document.write( "b) z2 + z + 1 = 0
\n" ); document.write( "c) (3)1/2y2 - 4y - 7(3)1/2 = 0
\n" ); document.write( "d) 2x2 - 10x + 25 = 0
\n" ); document.write( "e) 2x2 - 6x + 5 = 0
\n" ); document.write( "f) s2 - 4s + 4 = 0
\n" ); document.write( "g) 5/6x2 - 7x - 6/5 = 0
\n" ); document.write( "h) 7a2 + 8a + 2 = 0
\n" ); document.write( "2. If x = 1 and x = -8, then form a quadratic equation.
\n" ); document.write( "3. What type of solution do you get for quadratic equations where D < 0? Give reasons for your answer. Also provide an example of such a quadratic equation and find the solution of the equation.
\n" ); document.write( "4. Create a real-life situation that fits into the equation (x + 4)(x - 7) = 0 and express the situation as the same equation.
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Algebra.Com's Answer #127162 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
1. In the first place, ALL quadratic equations have two roots -- The Fundamental Theorem of Algebra says so. The question is, are the roots real numbers or not. Use the discriminant to make the determination.\r
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\n" ); document.write( "\n" ); document.write( "The discriminant is the part of the quadratic formula that is under the radical sign.\r
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\n" ); document.write( "\n" ); document.write( "Quadratic formula: \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" \r
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\n" ); document.write( "\n" ); document.write( "So the discriminant is: \"DELTA+=+b%5E2-4ac\"\r
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\n" ); document.write( "\n" ); document.write( "Use the discriminant to determine the character of the roots of a quadratic equation.\r
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\n" ); document.write( "\n" ); document.write( "if \"DELTA=0\" there is one real number root with a multiplicity of 2.\r
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\n" ); document.write( "\n" ); document.write( "if \"DELTA%3E0\" there are two real number roots.\r
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\n" ); document.write( "\n" ); document.write( "if \"DELTA%3C0\" there is a conjugate pair of complex roots of the form \"a%2B-bi\" \r
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\n" ); document.write( "\n" ); document.write( "I'll do the first one, and then you can do the rest:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B+6x+-+7+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "Here, \"a=1\", \"b=6\", and \"c=-7\", so \"DELTA=6%5E2-4%281%29%28-7%29=36%2B28=64%3E0\" so there are two real number roots.\r
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\n" ); document.write( "\n" ); document.write( "Simple as that. You can do the rest.\r
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\n" ); document.write( "\n" ); document.write( "2. To be exactly correct, this problem is incorrectly stated. \"x\" cannot simultaneously be \"1\" AND \"-8\". \"x=1\" OR \"x=-8\".\r
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\n" ); document.write( "\n" ); document.write( "Here's the rule: \"a\" is a root of a polynomial equation if and only if \"x-a\" is a factor of the polynomial.\r
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\n" ); document.write( "\n" ); document.write( "Since \"x=1\" OR \"x=-8\" are roots of the desired quadratic, then \"x-1\" and \"x%2B8\" must be factors of the quadratic polynomial, so just multiply \"%28x-1%29%28x%2B8%29\" and set the result equal to zero.\r
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\n" ); document.write( "\n" ); document.write( "3. This one is answered in the discussion for problem 1 above.\r
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\n" ); document.write( "\n" ); document.write( "4. No idea how to answer this one. You get zeros at -4 and 7, and a minimum value at 1.5 Your guess is as good as mine.
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