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You can put this solution on YOUR website!
f(x) = log10 (x^-8x+15)...THIS SHOULD BE log10 (x^2-8x+15)...I THINK
\n" ); document.write( " TO FIND DOMAIN OF X ,WE NEED TO FIND VALUES OF X THAT WILL PERMIT CALCULATION OF THE FUNCTION f(x) IN A MATHEMATICALLY MEANINGFULL OR PERMISSIBLE WAY ...
\n" ); document.write( " MATHEMATICALLY SPEAKING,DIVISION BY ZERO OR SQUARE ROOT OF NEGATIVE NUMBER OR LOG ZERO OR LOG NEGATIVE NUMBER HAVE NO MEANING.
\n" ); document.write( "HENCE WE SHOULD LOOK FOR AND AVOID SUCH SITUATIONS ...
\n" ); document.write( " HERE WE HAVE A LOG OF (x^2-8x+15) FUNCTION.SO (x^2-8x+15)=Y SAY SHOULD BE ONLY POSITIVE.SUCH VALUES OF X WHICH MAKE IT POSITIVE ARE ONLY PERMISSIBLE.HENCE THEY CONSTITUTE THE DOMAIN OF X
\n" ); document.write( "LET Y =(x^2-8x+15)>0
\n" ); document.write( "=X^2-5X-3X+15>0
\n" ); document.write( "=X(X-5)-3(X-5)>0
\n" ); document.write( "=(X-3)(X-5)>0...NOW , FOR A PRODUCT O 2 FACTORS TO BE POSITIVE ,EITHER BOTH FACTORS SHOULD BE NEGATIVE OR BOTH FACTORS SHOULD BE POSITIVE.HENCE
\n" ); document.write( "CASE 1......(X-3)<0 AND (X-5)<0...THAT IS
\n" ); document.write( "X<3 AND X<5 OR IN EFFECT X<3......CASE 1.
\n" ); document.write( "OR
\n" ); document.write( "CASE 2....(X-3)>0 AND (X-5)>0....THAT IS
\n" ); document.write( "X>3 AND X>5....OR INEFFECT X>5...CASE 2
\n" ); document.write( "HENCE THE DOMAIN OF X IS ALL X < 3 AND ALL X>5
\n" ); document.write( " \n" ); document.write( "