document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=172041>Question 172041</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve: log5(3x+1)=log5(2x+7)  the 5's are bases </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #127085 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=127085\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log5(3x+1)=log5(2x+7) the 5's are bases<BR>\n" );
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document.write( "If the logs (to the same base) are equal, the binomials are equal.<BR>\n" );
document.write( "3x+1 = 2x+7<BR>\n" );
document.write( "x = 6<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "log(19) = log(19) (to any base)\r<BR>\n" );
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