document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=171787>Question 171787</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars leave their respective towns ,wich are 1000 km appart, travelind towards each other. One cars leavesat 8 am and average 120km/h . The other car leaves at 9am and averages 100km/h. When and where will they meet each other? At what time will they be 500 kilometers apart? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #127068 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=127068\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two cars leave their respective towns, which are 1000 km apart, traveling<BR>\n" );
document.write( " towards each other. One cars leave sat 8 am and average 120km/h.<BR>\n" );
document.write( " The other car leaves at 9am and averages 100km/h.<BR>\n" );
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document.write( " When and where will they meet each other?<BR>\n" );
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document.write( "Let t = travel time of the 1st car<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(t-1) = travel time of the 2nd car<BR>\n" );
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document.write( "When they do meet, they will have traveled a total distance of 1000 km<BR>\n" );
document.write( "Write a distance equation from this fact: Dist = speed * time<BR>\n" );
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document.write( "1st car dist + 2nd car dist = 1000 km<BR>\n" );
document.write( "120t + 100(t-1) = 1000<BR>\n" );
document.write( "120t + 100t - 100 = 1000<BR>\n" );
document.write( "120t + 100t = 1000 + 100<BR>\n" );
document.write( "220t = 1100<BR>\n" );
document.write( "t = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1100%2F220 ALIGN=MIDDLE  ALT=\"1100%2F220\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "t = 5 hrs which will be 1 pm when they will meet<BR>\n" );
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document.write( "They will meet at 5*120 = 600 km from car 1's starting point<BR>\n" );
document.write( "or<BR>\n" );
document.write( "4 * 100 = 400 km from car 2's starting point (for a total 1000 km)<BR>\n" );
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document.write( " At what time will they be 500 kilometers apart?<BR>\n" );
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document.write( "They will have traveled half way, use the same equation to find t:<BR>\n" );
document.write( "120t + 100(t-1) = 500<BR>\n" );
document.write( "120t + 100t - 100 = 500<BR>\n" );
document.write( "120t + 100t = 500 + 100<BR>\n" );
document.write( "220t = 600<BR>\n" );
document.write( "t = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=600%2F220 ALIGN=MIDDLE  ALT=\"600%2F220\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "t = 2.72 hrs or 2 hrs 43.6 min which is 10:44<BR>\n" );
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document.write( "Check this<BR>\n" );
document.write( "2.73 * 120 = 328.0 km from car A starting point<BR>\n" );
document.write( "1.72 * 100 = 172.0 km from car B starting point<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "total driven 499.6 km ~ 500<BR>\n" );
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document.write( "A.............328>.....................<172.......B (1000)<BR>\n" );
document.write( "1000 - 328 - 172 = 500 km </SPAN>\n" );
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