document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=171999>Question 171999</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of two adjacent angles forms an angle of 143. The measure of the smaller angle is seven degrees more than one-third the measure of the larger angle. What are the measures of the two angles?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #127063 by </B><A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><B>KnightOwlTutor(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KnightOwlTutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=127063\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=larger angle\r<BR>\n" );
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document.write( "1/3x+7=smaller angle\r<BR>\n" );
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document.write( "x+1/3x+7=143\r<BR>\n" );
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document.write( "Subtract 7 from both sides\r<BR>\n" );
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document.write( "x+x1/3=136\r<BR>\n" );
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document.write( "1+1/3=4/3\r<BR>\n" );
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document.write( "4/3x=136\r<BR>\n" );
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document.write( "multiply each side by 3/4\r<BR>\n" );
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document.write( "x=(136)(3/4)\r<BR>\n" );
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document.write( "x=102\r<BR>\n" );
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document.write( "Let's doublecheck our answer\r<BR>\n" );
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document.write( "smaller angle is (1/3)(102)+7=41\r<BR>\n" );
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document.write( "102+41=143\r<BR>\n" );
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