document.write( "Question 171937: ten years ago, a man was 3 times as old as his son. in 6 years, he will be twice as old as his son. how old is each now? \n" ); document.write( "
Algebra.Com's Answer #127047 by ptaylor(2198)\"\" \"About 
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Let x=son's age now;
\n" ); document.write( "x-10=son's age ten years ago;
\n" ); document.write( "x+6=son's age in 6 years
\n" ); document.write( "And let y=man's age now;
\n" ); document.write( "y-10=man's age ten years ago;
\n" ); document.write( "y+6=man's age in 6 years\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now we are told the following:
\n" ); document.write( "y-10=3(x-10)=
\n" ); document.write( "y-10=3x-30=
\n" ); document.write( "3x-y=20----------------eq1
\n" ); document.write( "and
\n" ); document.write( "y+6=2(x+6)=
\n" ); document.write( "y+6=2x+12=
\n" ); document.write( "2x-y=-6------------------eq2
\n" ); document.write( "subtract eq2 from eq1:
\n" ); document.write( "x=26----------------------------son's age now
\n" ); document.write( "substitute x=26 into eq1:
\n" ); document.write( "3*26-y=20=
\n" ); document.write( "78-y=20
\n" ); document.write( "-y=-58
\n" ); document.write( "y=58-------------------man's age now\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "58-10=3(26-10)
\n" ); document.write( "48=48
\n" ); document.write( "and
\n" ); document.write( "58+6=2(26+6)
\n" ); document.write( "64=64\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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