document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=171956>Question 171956</A>: <I><SPAN STYLE=\"word-break: break-all;\">  The length of arectangular flower bed is 3 feet less than twice its width. the area of the bed is 54 square feet. find the dimensions of the flower bed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #127042 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=127042\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=2w-3<BR>\n" );
document.write( "Lw=54<BR>\n" );
document.write( ".<BR>\n" );
document.write( "w(2w-3)=54 substitute 2w-3 for L<BR>\n" );
document.write( "2w^2-3w-54=0<BR>\n" );
document.write( "2*-54=-108. -12 and 9 are the factors of -108 whose sum is -3.<BR>\n" );
document.write( "2w^2-12w+9w-54=0<BR>\n" );
document.write( "2w(w-6)+9(w-6)=0<BR>\n" );
document.write( "(2w+9)(w-6)=0<BR>\n" );
document.write( ".<BR>\n" );
document.write( "2w=-9<BR>\n" );
document.write( "w=-9/2 answer can't be negative.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "w=6'<BR>\n" );
document.write( "L=9'<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );