document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=171948>Question 171948</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My boyfriend and I were making up Algebra problems during a boring convention meal and ended up getting four different answers to this one.  It seems we have forgotten the Order of Operations.  (It's been a few years since either one of us was in school.)  What is the solution to this equation?  And, what is the order of operations?\r<BR>\n" );
document.write( "\n" );
document.write( "7/4(6+6+6) = 30*4/3(5-6)X\r<BR>\n" );
document.write( "\n" );
document.write( "Thank You;<BR>\n" );
document.write( "Brenda and Lee<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #127040 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=127040\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> http://regentsprep.org/Regents/math/orderop/Lorder.htm<BR>\n" );
document.write( ":<BR>\n" );
document.write( "the left side of the = (6+6+6) is added first = 18....next 7 is divided by 4 then you multiply that answer by 18\r<BR>\n" );
document.write( "\n" );
document.write( "so your left with 7(18)/4=31.5<BR>\n" );
document.write( ":<BR>\n" );
document.write( "the right side 5-6=-1...then 30*4=120 which is divided by 3 which is 40 which is multiplied by -1x.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "(120/3)(-1)=-40x\r<BR>\n" );
document.write( "\n" );
document.write( "so 31.5=-40x<BR>\n" );
document.write( ":<BR>\n" );
document.write( "x=31.5/-40=-.7875 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );