document.write( "Question 171943: how do you solve: log3(4x+1)=log3(5x-2), the 3's are the base numbers \n" ); document.write( "
Algebra.Com's Answer #127032 by stanbon(75887)\"\" \"About 
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solve: log3(4x+1)=log3(5x-2)
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\n" ); document.write( "\n" ); document.write( "log3(4x+1)-log3(5x-2) = 0\r
\n" ); document.write( "\n" ); document.write( "log3[(4x+1)/(5x-2)] = 0\r
\n" ); document.write( "\n" ); document.write( "[(4x+1)/(5x-2)] = 3^0\r
\n" ); document.write( "\n" ); document.write( "Cross-multiply to get:
\n" ); document.write( "4x+1 = 5x-2\r
\n" ); document.write( "\n" ); document.write( "x = 3
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\n" ); document.write( "Cheers,
\n" ); document.write( "stan H.\r
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