document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=171917>Question 171917</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 160 feet. Over the quarter was equal to <BR>\n" );
document.write( "twice the width. lasdimensiones find the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #127017 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=127017\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 160 feet. Over the quarter was equal to <BR>\n" );
document.write( "twice the width. lasdimensiones find the rectangle<BR>\n" );
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document.write( "I'm not sure I know what you mean.<BR>\n" );
document.write( "I'll assume you mean the length is twice the width. Find the dimensions.<BR>\n" );
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document.write( "Perimeter = 2(L+W) and L = 2W<BR>\n" );
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document.write( "Substitute to get:<BR>\n" );
document.write( "160 = 2(2W+W) <BR>\n" );
document.write( "80 = 3W<BR>\n" );
document.write( "Width = (80/3) feet<BR>\n" );
document.write( "Length = 2[80/3] = (160/3) feet<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );