document.write( "Question 171908: Subtract:
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document.write( "(x over x+10) - (3- x2 over x2-100)\r
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document.write( "Please help... \n" );
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Algebra.Com's Answer #127010 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! (x/(x+10)) - ((3- x^2)/(x^2-100))\r \n" ); document.write( "\n" ); document.write( "------------------------ \n" ); document.write( "lcd = x^2-100\r \n" ); document.write( "\n" ); document.write( "Rewrite both fractions with the lcd as denominator:\r \n" ); document.write( "\n" ); document.write( "[x(x-10)]/lcd - [-(x^2-3)]/lcd\r \n" ); document.write( "\n" ); document.write( "Combine the numerators over the lcd:\r \n" ); document.write( "\n" ); document.write( "= [x(x-10)+ (x^2-3)] /lcd\r \n" ); document.write( "\n" ); document.write( "= [x^2-10x+x^2-3]/lcd\r \n" ); document.write( "\n" ); document.write( "= [2x^2-10x-3]/[x^2-100]\r \n" ); document.write( "\n" ); document.write( "=========================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |