document.write( "Question 23979: 5x+1=36 \n" ); document.write( "
Algebra.Com's Answer #12699 by yhtong(11)\"\" \"About 
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Firstly you need to eliminate 1 at the left hand side (LHS) and bring it to the right hand side(RHS). In this case it will be -1 which is then be
\n" ); document.write( "5x=36-1 (Always leave the UNKNOWN ALONE)\r
\n" ); document.write( "\n" ); document.write( "continue by bringing the 5 in the 5x in the (LHS). This means 5*x, so when bringing it to the RHS, it will be /5 (divided by 5). that leaves
\n" ); document.write( "x=(36-1)/5
\n" ); document.write( "when you see that nothing is beside the unknown x, you can solve by solving the equation on the RHS which is (36-1)/5
\n" ); document.write( "answer is 35/5 which is =7
\n" ); document.write( " that leaves
\n" ); document.write( "x=7, thats the answer, x equals to 7.
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