document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=171880>Question 171880</A>: <I><SPAN STYLE=\"word-break: break-all;\"> E=(-4,K) AND F=(K,7) THE SLOPE OF EF IS 2/3, SOLVE FOR K </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #126974 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=126974\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> E=(-4,K) AND F=(K,7) THE SLOPE OF EF IS 2/3, SOLVE FOR K<BR>\n" );
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document.write( "slope = (7-K)/(K+4) = 2/3<BR>\n" );
document.write( "Cross-multiply to get:<BR>\n" );
document.write( "3(7-K) = 2(K+4)<BR>\n" );
document.write( "21-3K = 2K+8<BR>\n" );
document.write( "5K = 13<BR>\n" );
document.write( "K = 13/5<BR>\n" );
document.write( "=============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );