document.write( "Question 171875: how do you find the number of real solutions for this equation: x^2-10x+25=0? \n" ); document.write( "
Algebra.Com's Answer #126972 by stanbon(75887)\"\" \"About 
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how do you find the number of real solutions for this equation: x^2-10x+25=0?
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\n" ); document.write( "You evaluate the discriminant: b^2-4ac
\n" ); document.write( "Your discriminant = 10^2 - 4*1*25 = 100-100 = 0
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\n" ); document.write( "So the equation has two equal Real Number solutions.
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\n" ); document.write( "what are they?
\n" ); document.write( "Factor your problem and ou get:
\n" ); document.write( "(x-5)^2 = 0
\n" ); document.write( "So x = 5 with multiplicity two.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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