document.write( "Question 171875: how do you find the number of real solutions for this equation: x^2-10x+25=0? \n" ); document.write( "
Algebra.Com's Answer #126970 by jim_thompson5910(35256)\"\" \"About 
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To find the number of real solutions, simply use the discriminant formula \"D=b%5E2-4ac\". If \"D%3E0\", there are 2 real solutions. If \"D=0\", there's only one real solutions. Finally, if \"D%3C0\", then there are no real solutions.\r
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\n" ); document.write( "\n" ); document.write( "From \"x%5E2-10x%2B25\" we can see that \"a=1\", \"b=-10\", and \"c=25\"\r
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\n" ); document.write( "\n" ); document.write( "\"D=b%5E2-4ac\" Start with the discriminant formula.\r
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\n" ); document.write( "\n" ); document.write( "\"D=%28-10%29%5E2-4%281%29%2825%29\" Plug in \"a=1\", \"b=-10\", and \"c=25\"\r
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\n" ); document.write( "\n" ); document.write( "\"D=100-4%281%29%2825%29\" Square \"-10\" to get \"100\"\r
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\n" ); document.write( "\n" ); document.write( "\"D=100-100\" Multiply \"4%281%29%2825%29\" to get \"%284%29%2825%29=100\"\r
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\n" ); document.write( "\n" ); document.write( "\"D=0\" Subtract \"100\" from \"100\" to get \"0\"\r
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\n" ); document.write( "\n" ); document.write( "Since the discriminant is equal to zero, this means that there is one real solution.
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