document.write( "Question 171795This question is from textbook Algebra and Trigonometry: Structure and Method-Book 2
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document.write( ": Pam jogged up a hill at 6 km/h and then jogged back down at 10 km/h. If her total jogging time was 1 h 20 min, how many km did she travel? \n" );
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Algebra.Com's Answer #126929 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=R*T \n" ); document.write( "6*X=10(4/3-X) [4/3=1H. 20M.] \n" ); document.write( "6X=40/3-10X \n" ); document.write( "6X+10X=40/3 \n" ); document.write( "16X=40/3 \n" ); document.write( "X=40/3*1/16 \n" ); document.write( "X=40/48 \n" ); document.write( "X=5/6 HOURS FOR THE UP HILL RUN. \n" ); document.write( "10(4/3-5/6) \n" ); document.write( "10(4*4-5*2)/12 \n" ); document.write( "10(16-10)/12 \n" ); document.write( "10*6/12 \n" ); document.write( "60/12=5 M. IS THE RUN DOWN THE HILL. \n" ); document.write( "6*5/6=30/6=5 M. UP THE HILL \n" ); document.write( "tOTAL RUN=2*5=10 M. IS THE TOTAL RUN DISTANCE. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |