document.write( "Question 171795This question is from textbook Algebra and Trigonometry: Structure and Method-Book 2
\n" ); document.write( ": Pam jogged up a hill at 6 km/h and then jogged back down at 10 km/h. If her total jogging time was 1 h 20 min, how many km did she travel? \n" ); document.write( "
Algebra.Com's Answer #126929 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
D=R*T
\n" ); document.write( "6*X=10(4/3-X) [4/3=1H. 20M.]
\n" ); document.write( "6X=40/3-10X
\n" ); document.write( "6X+10X=40/3
\n" ); document.write( "16X=40/3
\n" ); document.write( "X=40/3*1/16
\n" ); document.write( "X=40/48
\n" ); document.write( "X=5/6 HOURS FOR THE UP HILL RUN.
\n" ); document.write( "10(4/3-5/6)
\n" ); document.write( "10(4*4-5*2)/12
\n" ); document.write( "10(16-10)/12
\n" ); document.write( "10*6/12
\n" ); document.write( "60/12=5 M. IS THE RUN DOWN THE HILL.
\n" ); document.write( "6*5/6=30/6=5 M. UP THE HILL
\n" ); document.write( "tOTAL RUN=2*5=10 M. IS THE TOTAL RUN DISTANCE. \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );