document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=171750>Question 171750</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0918091802/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 8 feet less than twice the width. if 260 feet of fencing is needed to close in the yard, find the dimensions of the yard </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #126871 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=126871\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=2W-8<BR>\n" );
document.write( "PERIMETER=2L+2W<BR>\n" );
document.write( "260=2(2W-8)+2W<BR>\n" );
document.write( "260=4W-16+2W<BR>\n" );
document.write( "260=4W-16+2W<BR>\n" );
document.write( "6W=260+16<BR>\n" );
document.write( "6W=276<BR>\n" );
document.write( "W=276/6<BR>\n" );
document.write( "W=46 FT FOR THE WIDTH<BR>\n" );
document.write( "L=2*46-8<BR>\n" );
document.write( "L=92-8<BR>\n" );
document.write( "L=84 FT FOR THE LENGTH<BR>\n" );
document.write( "pROOF:<BR>\n" );
document.write( "260=2*84+2*46<BR>\n" );
document.write( "260=168+92<BR>\n" );
document.write( "260=260 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );