document.write( "Question 171683: How many zeros does P(x) have and list all the possible suspects for finding the real zeros for P(x).\r
\n" ); document.write( "\n" ); document.write( "P(x)=x^4+6x^3+6x^2+2x+8
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Algebra.Com's Answer #126860 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
How many zeros does P(x) have and list all the possible suspects for finding the real zeros for P(x).
\n" ); document.write( "P(x)=x^4+6x^3+6x^2+2x+8
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\n" ); document.write( "How many?: four because the degree of the polynomial is four.
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\n" ); document.write( "Real Number Candidates:
\n" ); document.write( "If p/q is a zero, p must be a divisor of 8 and q must be a divisor of 1
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\n" ); document.write( "+-1,+-2,+-4,+-8 are the possibilities
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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