document.write( "Question 171715This question is from textbook
\n" ); document.write( ": I got three different answer can someone please put me on the right track \r
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\n" ); document.write( "\n" ); document.write( "Walt made an extra $9000 last year from a part-time job. He invested part of the money at 9% and the rest at 8%. He made a total of $770 in interest. How much was invested at 8%?
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Algebra.Com's Answer #126859 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Interest(I)=Principal(P)*Rate(R)*Time(T)\r
\n" ); document.write( "\n" ); document.write( "Let x=amount invested at 8%
\n" ); document.write( "Then 9000-x=amount invested at 9%
\n" ); document.write( "Interest at 8%=x*0.08*1=0.08x
\n" ); document.write( "Interest at 9%=(9000-x)*0.09*1=0.09(9000-x)
\n" ); document.write( "And we are told that the above interest adds up to 770, so:
\n" ); document.write( "0.08x+0.09(9000-x)=770 get rid of parens
\n" ); document.write( "0.08x+810-0.09x=770 subtract 810 from each side
\n" ); document.write( "0.08x+810-810-0.09x=770-810 collect like terms
\n" ); document.write( "-0.01x=-40 divide each side by-0.01
\n" ); document.write( "x=$4000--------------------amount invested at 8%
\n" ); document.write( "9000-x=9000-4000=$5000---------amount invested at 9%
\n" ); document.write( "CK
\n" ); document.write( "0.08*4000+0.09*5000=770
\n" ); document.write( "320+450=770
\n" ); document.write( "770=770\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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