document.write( "Question 171646This question is from textbook Algebra and Trigonometry Structure and Method Book 2
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document.write( ": Tim paddled his kayak 12 km upstream against a 3 km/h current and back again in 5 h 20 min. In that time how far could he have paddled in still water? \n" );
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Algebra.Com's Answer #126819 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Tim paddled his kayak 12 km upstream against a 3 km/h current and back again \n" ); document.write( " in 5 h 20 min. In that time how far could he have paddled in still water? \n" ); document.write( ": \n" ); document.write( "Let s = his speed in still water \n" ); document.write( "then \n" ); document.write( "(s-3) = his speed upstream \n" ); document.write( "and \n" ); document.write( "(s+3) = his speed downstream \n" ); document.write( "; \n" ); document.write( "Write a time equation: time = \n" ); document.write( ": \n" ); document.write( "Change 5 hr 20 min to hrs: 5 \n" ); document.write( ": \n" ); document.write( "Time upstream + time downstream = 5 \n" ); document.write( " \n" ); document.write( "Multiply equation by 3(s-3)(s+3) \n" ); document.write( "3(s-3)(s+3)* \n" ); document.write( "Results: \n" ); document.write( "36(s+3) + 36(s-3) = 16(s-3)(s+3) \n" ); document.write( ": \n" ); document.write( "36s + 108 + 36s - 108 = 16(s^2 - 9) \n" ); document.write( ": \n" ); document.write( "72s = 16s^2 - 144 \n" ); document.write( "Arrange as a quadratic equation: \n" ); document.write( "16s^2 - 72s - 144 = 0 \n" ); document.write( "Simplify divide equation by 8 \n" ); document.write( "2s^2 - 9s - 18 = 0 \n" ); document.write( "Factor \n" ); document.write( "(2s + 3)(s - 6) = 0 \n" ); document.write( "Positive solution: \n" ); document.write( "s = 6 mph; his still water speed \n" ); document.write( ": \n" ); document.write( "How far would he travel in 5 \n" ); document.write( "6 * \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by find the times \n" ); document.write( "12/9 = 1.33 \n" ); document.write( "12/3 = 4.0 \n" ); document.write( "Total= 5.33 hrs \n" ); document.write( " |