document.write( "Question 171692: Could you please help me with this problem? I have a hard time figuring out how to set up word problems...\r
\n" ); document.write( "\n" ); document.write( "The perimeter of a picture frame is 11 feet. If three times the height is equal to eight times the width, what are the dimensions of the frame?\r
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Algebra.Com's Answer #126815 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let x=width and y=height\r
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\n" ); document.write( "\n" ); document.write( "\"The perimeter of a picture frame is 11 feet\" translates to \"11=2x%2B2y\". Note: remember, the perimeter formula is \"P=2L%2B2W\" where L and W are the length and width\r
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\n" ); document.write( "\n" ); document.write( "\"three times the height is equal to eight times the width\" translates to \"3y=8x\"\r
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\n" ); document.write( "\n" ); document.write( "\"3y=8x\" Start with the second equation\r
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\n" ); document.write( "\n" ); document.write( "\"y=%288x%29%2F3\" Divide both sides by 3 to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"11=2x%2B2y\" Go back to the first equation\r
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\n" ); document.write( "\n" ); document.write( "\"11=2x%2B2%28%288x%29%2F3%29\" Plug in \"y=%288x%29%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"11=2x%2B%2816x%29%2F3\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"3%2811%29=3%282x%29%2Bcross%283%29%28%2816x%29%2Fcross%283%29%29\" Multiply EVERY term by the LCD 3 to clear the fraction.\r
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\n" ); document.write( "\n" ); document.write( "\"33=6x%2B16x\" Multiply and simplify\r
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\n" ); document.write( "\n" ); document.write( "\"33=22x\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"33%2F22=x\" Divide both sides by 22 to isolate \"x\"\r
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\n" ); document.write( "\n" ); document.write( "\"3%2F2=x\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So the first answer is \"x=3%2F2\" (which in decimal form is \"x=1.5\")\r
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\n" ); document.write( "\n" ); document.write( "\"y=%288x%29%2F3\" Go back to the isolated equation\r
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\n" ); document.write( "\n" ); document.write( "\"y=%288%283%2F2%29%29%2F3\" Plug in \"x=3%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%2812%29%2F3\" Multiply 8 and \"3%2F2\" to get \"8%283%2F2%29=24%2F2=12\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=4\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So the second answer is \"y=4\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the answers are \"x=3%2F2\" (which in decimal form is \"x=1.5\") and \"y=4\"\r
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\n" ); document.write( "\n" ); document.write( "This means that the width is 1.5 feet and the height is 4 feet.
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