document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=171656>Question 171656</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Divide\r<BR>\n" );
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document.write( "x^3-8/x+2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #126812 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=126812\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Apply the special case of sum/difference of cubes:<BR>\n" );
document.write( "X^3+ Y^3 = (x + y)(X^2 - XY + Y^2 )<BR>\n" );
document.write( "X^3 -^Y3 = (X - Y)(X^2 + XY + Y^2 )<BR>\n" );
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document.write( "In your case, it's the second one:<BR>\n" );
document.write( "So<BR>\n" );
document.write( "x^3-8/x+2<BR>\n" );
document.write( "after factoring the numerator becomes:<BR>\n" );
document.write( "(x+2)(x^2 -2x + 4)/(x+2)<BR>\n" );
document.write( "canceling like-terms we get:<BR>\n" );
document.write( "x^2 -2x + 4<BR>\n" );
document.write( " </SPAN>\n" );
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