document.write( "Question 171680: Three painters can finish painting a wall in 10 minutes. The first painter can finish a wall in 20 minutes and the second one can do it in 30 minutes. How long would it take the third painter to do the job alone. \n" ); document.write( "
Algebra.Com's Answer #126805 by stanbon(75887)\"\" \"About 
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Three painters can finish painting a wall in 10 minutes. The first painter can finish a wall in 20 minutes and the second one can do it in 30 minutes. How long would it take the third painter to do the job alone.
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\n" ); document.write( "1st painter DATA
\n" ); document.write( "Time = 20 min/job ; rate = 1/20 job/min
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\n" ); document.write( "2nd painter DATA:
\n" ); document.write( "Time = 30 min/job ; rate = 1/30 job/min
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\n" ); document.write( "3rd painter DATA:
\n" ); document.write( "Time = x min/job ; rate = 1/x job/min
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\n" ); document.write( "Together DATA:
\n" ); document.write( "Time = 10 min/job ;rate = 1/10 job/min
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\n" ); document.write( "EQUATION:
\n" ); document.write( "rate + rate + rate = together rate
\n" ); document.write( "1/20 + 1/30 + 1/x = 1/10\r
\n" ); document.write( "\n" ); document.write( "Multiply thru by 60x to get:
\n" ); document.write( "3x + 2x + 60 = 6x
\n" ); document.write( "x = 60 minutes (time for the 3rd painter to do the job)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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