document.write( "Question 171635: Two men start from the same corner \"A\", going in different directions around a field 1 mile square. The man going along AB walks 4 miles an hour, and the other man who is traveling AD goes 3 miles an hour. Where and after how long will they meet? \n" ); document.write( "
Algebra.Com's Answer #126789 by ankor@dixie-net.com(22740)\"\" \"About 
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Two men start from the same corner \"A\", going in different directions around a field 1 mile square. The man going along AB walks 4 miles an hour, and the other man who is traveling AD goes 3 miles an hour. Where and after how long will they meet?
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\n" ); document.write( "The perimeter (ABCD) of the square = 4 mi
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\n" ); document.write( "The two men will have traveled a total distance of 4 mi when they meet.
\n" ); document.write( "there:
\n" ); document.write( "Let d = distance traveled by the 1st guy when they meet from \"A\"
\n" ); document.write( "Then
\n" ); document.write( "(4-d) = distance traveled by the 2nd guy when they meet
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\n" ); document.write( "The travel times of both men will be the same
\n" ); document.write( "Write time equation: Time = \"dist%2Fspeed\"
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\n" ); document.write( "A's time = B's time
\n" ); document.write( "\"d%2F4\" = \"%284-d%29%2F3\"
\n" ); document.write( "Cross multiply to find d
\n" ); document.write( "3d = 4(4-d)
\n" ); document.write( "3d = 16 - 4d
\n" ); document.write( "3d + 4d = 16
\n" ); document.write( "7d = 16
\n" ); document.write( "d = \"16%2F7\" miles traveled by the 1st guy
\n" ); document.write( "Which would put him between C & D, actually 2/7 mi from C
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\n" ); document.write( "Find the travel time of A, who is traveling 4 mph:
\n" ); document.write( "\"16%2F7\" * \"1%2F4\" = \"4%2F7\" hrs or 34.3 min
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\n" ); document.write( "Check solution using the 2nd man traveling 3 mph, find his distance (4-d)
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\n" ); document.write( "4 - \"16%2F7\" = \"28%2F7\" - \"16%2F7\" = \"12%2F7\" mi for the 2nd guy
\n" ); document.write( "That would put him between D & C, actually 5/7 mi from D
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\n" ); document.write( "Find the travel time of the 2nd guy who is traveling at 3 mph
\n" ); document.write( "\"12%2F7\" * \"1%2F3\" = \"4%2F7\" hrs or 34.3 min as it should be;
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\n" ); document.write( "Did this procedure make sense to you?
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