document.write( "Question 171639This question is from textbook
\n" ); document.write( ": Please double check my work\r
\n" ); document.write( "\n" ); document.write( "Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Find the probability. The first marble is white and the second marble is blue.\r
\n" ); document.write( "\n" ); document.write( "p(white) = 3/8
\n" ); document.write( "p(green) = 2/8 = 1/4
\n" ); document.write( "p(red) = 2/8 = 1/4
\n" ); document.write( "p(blue) = 1/8\r
\n" ); document.write( "\n" ); document.write( "I came up with the answer of 6/8. Am I right? \n" ); document.write( "

Algebra.Com's Answer #126784 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
This is a case of \"sampling without replacement\"
\n" ); document.write( "In this problem, you first find the probability that a white marble is drawn, expressed as $\"P%28W%29\"$ . You have correctly found this to be $\"P%28W%29+=+3%2F8\"$ .
\n" ); document.write( "Now, you need to find the probabilty that a blue marble was next drawn, given that a white marble was previously drawn. This is expressed as P(B|W) and, because there are now only 7 marbles (from an initial 8 marbles) in the bag, this would be expressed as: P(B|W) = 1/7.
\n" ); document.write( "Now you can find the probability that the first marble drawn (without replacement) was white and the second mable was blue:
\n" ); document.write( "P(W and B) = P(W)*P(B|W) = $\"%283%2F8%29%2A%281%2F7%29=+3%2F56\"$ = $\"0.0536\"$ \n" ); document.write( "

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