document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=171564>Question 171564</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is (bcubed+8squared)-(3b-24) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #126772 by </B><A HREF=/tutors/aboutme.mpl?userid=midwood_trail><B>midwood_trail(310)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=midwood_trail><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=126772\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I guess this is what you are trying to express:\r<BR>\n" );
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document.write( "b^3 + 8^2 - (3b - 24)\r<BR>\n" );
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document.write( "Simplify one step at a time.\r<BR>\n" );
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document.write( "b^3 + 64 - 3b + 24\r<BR>\n" );
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document.write( "Combine like terms.\r<BR>\n" );
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document.write( "(b^3 - 3b) + (64 + 24)\r<BR>\n" );
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document.write( "Factor the quantity (b^3 - 3b).\r<BR>\n" );
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document.write( "So, (b^3 - 3b) becomes b(b^2 - 3).\r<BR>\n" );
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document.write( "Of course, 64 + 24 = 88.\r<BR>\n" );
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document.write( "We now put it all together.\r<BR>\n" );
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document.write( "b(b^2 - 3) + 88\r<BR>\n" );
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document.write( "This is the answer based on what you typed.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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