document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=171634>Question 171634</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the number of degrees in each angle of a triangle if the first angle is twice the second and three times the third in value. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #126771 by </B><A HREF=/tutors/aboutme.mpl?userid=midwood_trail><B>midwood_trail(310)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=midwood_trail><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=126771\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the number of degrees in each angle of a triangle if the first angle is twice the second and three times the third in value.\r<BR>\n" );
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document.write( "The total measure of the angles in any triangle = 180 degrees.\r<BR>\n" );
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document.write( "Each triangle has 3 angles.\r<BR>\n" );
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document.write( "Here are the 3 angles:\r<BR>\n" );
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document.write( "first angle = 2x\r<BR>\n" );
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document.write( "second angle = x\r<BR>\n" );
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document.write( "third angle = 3x\r<BR>\n" );
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document.write( "2x + x + 3x = 180\r<BR>\n" );
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document.write( "6x = 180\r<BR>\n" );
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document.write( "x = 180/6\r<BR>\n" );
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document.write( "x = 30\r<BR>\n" );
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document.write( "Now, replace x with 30 for each given angle.\r<BR>\n" );
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document.write( "first angle = 2x = 2(30) = 60\r<BR>\n" );
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document.write( "second angle = x = 30\r<BR>\n" );
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document.write( "third angle = 3x = 3(30) = 90\r<BR>\n" );
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document.write( "Did you follow?\r<BR>\n" );
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