document.write( "Question 171619This question is from textbook Introductory Algebra
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document.write( ": Solve.\r
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document.write( "12/sqrt 5x + 6 = sqrt 2x + 5 \n" );
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Algebra.Com's Answer #126760 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 12/sqrt(5x + 6) = sqrt(2x + 5)\r \n" ); document.write( "\n" ); document.write( "Multiply thru by sqrt(5x+6) to get: \n" ); document.write( "12 = sqrt[2x+5)(5x+6)] \n" ); document.write( "---- \n" ); document.write( "Square both sides to get: \n" ); document.write( "144 = 10x^2 + 37x +30 \n" ); document.write( "10x^2 + 37x - 114 = 0 \n" ); document.write( "Use the quadratic formula to get:\r \n" ); document.write( "\n" ); document.write( "x = [-37 +- sqrt(5929)]/20\r \n" ); document.write( "\n" ); document.write( "x = [-37 +- 77]/20\r \n" ); document.write( "\n" ); document.write( "x = 2 or x = -114/20 \n" ); document.write( "========================== \n" ); document.write( "2 is a solution; -114/20 is extraneous \n" ); document.write( "============================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |