document.write( "Question 171588: Please find the middle term in the expansion of
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document.write( "(x/3 + 9y)^10 \n" );
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Algebra.Com's Answer #126751 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "You will need to apply the \"binomial theorem\" \n" ); document.write( "See this site for a review: \n" ); document.write( "http://www.purplemath.com/modules/binomial.htm \n" ); document.write( ". \n" ); document.write( "The nth term is: \n" ); document.write( "C(n,k)a^(n-k)b^k \n" ); document.write( "where \n" ); document.write( "C(n,k) = n!/(n-k)!k! \n" ); document.write( ". \n" ); document.write( "In this case, \n" ); document.write( "k = 4 (desired term minus 1) \n" ); document.write( "n = 10 \n" ); document.write( ". \n" ); document.write( "therefore, \n" ); document.write( "C(10,4)a^(10-4)b^4 \n" ); document.write( ". \n" ); document.write( "C(n,k) = n!/(n-k)!k! \n" ); document.write( "C(10,4) = 10!/(10-4)!4! \n" ); document.write( "C(10,4) = 10!/6!4! \n" ); document.write( "C(10,4) = (7*8*9*10)/(1*2*3*4) = 120960 \n" ); document.write( ". \n" ); document.write( "So, \n" ); document.write( "C(10,4)a^(10-4)b^4 \n" ); document.write( "120960a^6b^4 \n" ); document.write( "120960(x/3)^6(9y)^4 \n" ); document.write( "120960(x^6/729)(9y)^4 \n" ); document.write( "165.9259(x^6)(6561y^4) \n" ); document.write( "1088640x^6y^4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |